Base | Representation |
---|---|
bin | 1100110001111111111000… |
… | …0110111000101111010001 |
3 | 1211202110111210021121111000 |
4 | 3030133332012320233101 |
5 | 3320221222404241340 |
6 | 45515523335012213 |
7 | 2650205643440103 |
oct | 314377606705721 |
9 | 54673453247430 |
10 | 14053101243345 |
11 | 452898331976a |
12 | 16ab70320a069 |
13 | 7ac2813658b8 |
14 | 3682609db573 |
15 | 195847b84d30 |
hex | cc7fe1b8bd1 |
14053101243345 has 64 divisors (see below), whose sum is σ = 25128379434240. Its totient is φ = 7451579349504.
The previous prime is 14053101243299. The next prime is 14053101243359. The reversal of 14053101243345 is 54334210135041.
14053101243345 is a `hidden beast` number, since 1 + 4 + 0 + 5 + 310 + 1 + 2 + 4 + 334 + 5 = 666.
It is not a de Polignac number, because 14053101243345 - 26 = 14053101243281 is a prime.
It is an unprimeable number.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 16678354 + ... + 17500676.
It is an arithmetic number, because the mean of its divisors is an integer number (392630928660).
Almost surely, 214053101243345 is an apocalyptic number.
14053101243345 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
It is an amenable number.
14053101243345 is a deficient number, since it is larger than the sum of its proper divisors (11075278190895).
14053101243345 is a wasteful number, since it uses less digits than its factorization.
14053101243345 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 823071 (or 823065 counting only the distinct ones).
The product of its (nonzero) digits is 86400, while the sum is 36.
Adding to 14053101243345 its reverse (54334210135041), we get a palindrome (68387311378386).
The spelling of 14053101243345 in words is "fourteen trillion, fifty-three billion, one hundred one million, two hundred forty-three thousand, three hundred forty-five".
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