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14053164803 = 98897142099
BaseRepresentation
bin11010001011010001…
…00100011100000011
31100021101111201222022
431011220210130003
5212240102233203
610242252032055
71005151633646
oct150550443403
940241451868
1014053164803
115a61710797
12288246262b
13142c634942
14974595a5d
15573b35a38
hex345a24703

14053164803 has 4 divisors (see below), whose sum is σ = 14053405800. Its totient is φ = 14052923808.

The previous prime is 14053164799. The next prime is 14053164817. The reversal of 14053164803 is 30846135041.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 30846135041 = 291063659829.

It is a cyclic number.

It is not a de Polignac number, because 14053164803 - 22 = 14053164799 is a prime.

It is a super-3 number, since 3×140531648033 (a number of 31 digits) contains 333 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (14053164833) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 27848 + ... + 169946.

It is an arithmetic number, because the mean of its divisors is an integer number (3513351450).

Almost surely, 214053164803 is an apocalyptic number.

14053164803 is a deficient number, since it is larger than the sum of its proper divisors (240997).

14053164803 is an equidigital number, since it uses as much as digits as its factorization.

14053164803 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 240996.

The product of its (nonzero) digits is 34560, while the sum is 35.

Adding to 14053164803 its reverse (30846135041), we get a palindrome (44899299844).

The spelling of 14053164803 in words is "fourteen billion, fifty-three million, one hundred sixty-four thousand, eight hundred three".

Divisors: 1 98897 142099 14053164803