Base | Representation |
---|---|
bin | 11111111101000001000001… |
… | …101101010001011111110001 |
3 | 200102120202202211120102102202 |
4 | 133331001001231101133301 |
5 | 121404440410132443210 |
6 | 1214515412543152545 |
7 | 41413063452210005 |
oct | 3775010155213761 |
9 | 612522684512382 |
10 | 140532432312305 |
11 | 40861519404a30 |
12 | 139181632a5755 |
13 | 60551c7b137c7 |
14 | 269bb3d9ca705 |
15 | 113a8875539a5 |
hex | 7fd041b517f1 |
140532432312305 has 16 divisors (see below), whose sum is σ = 183969995083200. Its totient is φ = 102205257812160.
The previous prime is 140532432312289. The next prime is 140532432312319. The reversal of 140532432312305 is 503213234235041.
It is not a de Polignac number, because 140532432312305 - 24 = 140532432312289 is a prime.
It is a super-2 number, since 2×1405324323123052 (a number of 29 digits) contains 22 as substring.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 49484186 + ... + 52247004.
It is an arithmetic number, because the mean of its divisors is an integer number (11498124692700).
Almost surely, 2140532432312305 is an apocalyptic number.
It is an amenable number.
140532432312305 is a deficient number, since it is larger than the sum of its proper divisors (43437562770895).
140532432312305 is a wasteful number, since it uses less digits than its factorization.
140532432312305 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3687664.
The product of its (nonzero) digits is 259200, while the sum is 38.
Adding to 140532432312305 its reverse (503213234235041), we get a palindrome (643745666547346).
The spelling of 140532432312305 in words is "one hundred forty trillion, five hundred thirty-two billion, four hundred thirty-two million, three hundred twelve thousand, three hundred five".
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