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140534443202044 = 2235133610800511
BaseRepresentation
bin11111111101000010111001…
…100100001101010111111100
3200102120221221222102012120111
4133331002321210031113330
5121410004014424431134
61214520344255355404
741413164340405213
oct3775027144152774
9612527858365514
10140534443202044
114086236050a181
1213918624822b64
1360554586016a8
14269bc90abc07a
15113a953d67c64
hex7fd0b990d5fc

140534443202044 has 6 divisors (see below), whose sum is σ = 245935275603584. Its totient is φ = 70267221601020.

The previous prime is 140534443202017. The next prime is 140534443202059. The reversal of 140534443202044 is 440202344435041.

It is a super-2 number, since 2×1405344432020442 (a number of 29 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 140534443201988 and 140534443202006.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 17566805400252 + ... + 17566805400259.

Almost surely, 2140534443202044 is an apocalyptic number.

It is an amenable number.

140534443202044 is a deficient number, since it is larger than the sum of its proper divisors (105400832401540).

140534443202044 is a wasteful number, since it uses less digits than its factorization.

140534443202044 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 35133610800515 (or 35133610800513 counting only the distinct ones).

The product of its (nonzero) digits is 737280, while the sum is 40.

Adding to 140534443202044 its reverse (440202344435041), we get a palindrome (580736787637085).

The spelling of 140534443202044 in words is "one hundred forty trillion, five hundred thirty-four billion, four hundred forty-three million, two hundred two thousand, forty-four".

Divisors: 1 2 4 35133610800511 70267221601022 140534443202044