Base | Representation |
---|---|
bin | 1100110010000011100110… |
… | …1110001100100111010011 |
3 | 1211202120002111021001010111 |
4 | 3030200321232030213103 |
5 | 3320230244424412430 |
6 | 45520210503542151 |
7 | 2650242506610523 |
oct | 314407156144723 |
9 | 54676074231114 |
10 | 14054101404115 |
11 | 4529346942313 |
12 | 16ab94215a957 |
13 | 7ac3b062acc6 |
14 | 36831778b683 |
15 | 1958a5898c2a |
hex | cc839b8c9d3 |
14054101404115 has 32 divisors (see below), whose sum is σ = 17763342105600. Its totient is φ = 10645056132480.
The previous prime is 14054101404113. The next prime is 14054101404131. The reversal of 14054101404115 is 51140410145041.
14054101404115 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 14054101404115 - 21 = 14054101404113 is a prime.
It is not an unprimeable number, because it can be changed into a prime (14054101404113) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 1922845081 + ... + 1922852389.
It is an arithmetic number, because the mean of its divisors is an integer number (555104440800).
Almost surely, 214054101404115 is an apocalyptic number.
14054101404115 is a deficient number, since it is larger than the sum of its proper divisors (3709240701485).
14054101404115 is a wasteful number, since it uses less digits than its factorization.
14054101404115 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 16867.
The product of its (nonzero) digits is 6400, while the sum is 31.
Adding to 14054101404115 its reverse (51140410145041), we get a palindrome (65194511549156).
The spelling of 14054101404115 in words is "fourteen trillion, fifty-four billion, one hundred one million, four hundred four thousand, one hundred fifteen".
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