140543110214441 has 4 divisors (see below), whose sum is σ = 153319756597584. Its totient is φ = 127766463831300.

The previous prime is 140543110214431. The next prime is 140543110214501. The reversal of 140543110214441 is 144412011345041.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-140543110214441 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (140543110214431) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6388323191555 + ... + 6388323191576.

It is an arithmetic number, because the mean of its divisors is an integer number (38329939149396).

Almost surely, 2^{140543110214441} is an apocalyptic number.

140543110214441 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

It is an amenable number.

140543110214441 is a deficient number, since it is larger than the sum of its proper divisors (12776646383143).

140543110214441 is a wasteful number, since it uses less digits than its factorization.

140543110214441 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 12776646383142.

The product of its (nonzero) digits is 30720, while the sum is 35.

Adding to 140543110214441 its reverse (144412011345041), we get a palindrome (284955121559482).

The spelling of 140543110214441 in words is "one hundred forty trillion, five hundred forty-three billion, one hundred ten million, two hundred fourteen thousand, four hundred forty-one".