14055041115 has 48 divisors (see below), whose sum is σ = 24988953600. Its totient is φ = 7305043200.

The previous prime is 14055041101. The next prime is 14055041129. The reversal of 14055041115 is 51114055041.

14055041115 is a `hidden beast` number, since 1 + 40 + 5 + 504 + 1 + 115 = 666.

It is an interprime number because it is at equal distance from previous prime (14055041101) and next prime (14055041129).

It is not a de Polignac number, because 14055041115 - 2⁵ = 14055041083 is a prime.

It is an unprimeable number.

It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 335590 + ... + 375140.

It is an arithmetic number, because the mean of its divisors is an integer number (520603200).

Almost surely, 2^14055041115 is an apocalyptic number.

14055041115 is a gapful number since it is divisible by the number (15) formed by its first and last digit.

14055041115 is a deficient number, since it is larger than the sum of its proper divisors (10933912485).

14055041115 is a wasteful number, since it uses less digits than its factorization.

14055041115 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 39764 (or 39761 counting only the distinct ones).

The product of its (nonzero) digits is 2000, while the sum is 27.

Adding to 14055041115 its reverse (51114055041), we get a palindrome (65169096156).

The spelling of 14055041115 in words is "fourteen billion, fifty-five million, forty-one thousand, one hundred fifteen".