14055041131 has 2 divisors, whose sum is σ = 14055041132. Its totient is φ = 14055041130.

The previous prime is 14055041129. The next prime is 14055041137. The reversal of 14055041131 is 13114055041.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 14055041131 - 2¹ = 14055041129 is a prime.

It is a super-2 number, since 2×14055041131² (a number of 21 digits) contains 22 as substring.

Together with 14055041129, it forms a pair of twin primes.

It is a junction number, because it is equal to n+sod(n) for n = 14055041096 and 14055041105.

It is not a weakly prime, because it can be changed into another prime (14055041137) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7027520565 + 7027520566.

It is an arithmetic number, because the mean of its divisors is an integer number (7027520566).

Almost surely, 2^14055041131 is an apocalyptic number.

14055041131 is a deficient number, since it is larger than the sum of its proper divisors (1).

14055041131 is an equidigital number, since it uses as much as digits as its factorization.

14055041131 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1200, while the sum is 25.

Adding to 14055041131 its reverse (13114055041), we get a palindrome (27169096172).

The spelling of 14055041131 in words is "fourteen billion, fifty-five million, forty-one thousand, one hundred thirty-one".