14055215400003 has 4 divisors (see below), whose sum is σ = 18740287200008. Its totient is φ = 9370143600000.

The previous prime is 14055215400001. The next prime is 14055215400047. The reversal of 14055215400003 is 30000451255041.

It is a semiprime because it is the product of two primes.

It is not a de Polignac number, because 14055215400003 - 2¹ = 14055215400001 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (14055215400001) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2342535899998 + ... + 2342535900003.

It is an arithmetic number, because the mean of its divisors is an integer number (4685071800002).

Almost surely, 2^{14055215400003} is an apocalyptic number.

14055215400003 is a deficient number, since it is larger than the sum of its proper divisors (4685071800005).

14055215400003 is an equidigital number, since it uses as much as digits as its factorization.

14055215400003 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4685071800004.

The product of its (nonzero) digits is 12000, while the sum is 30.

Adding to 14055215400003 its reverse (30000451255041), we get a palindrome (44055666655044).

The spelling of 14055215400003 in words is "fourteen trillion, fifty-five billion, two hundred fifteen million, four hundred thousand, three".