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14055530240183 is a prime number
BaseRepresentation
bin1100110010001000111011…
…1000110001100010110111
31211202200210001212102201212
43030202032320301202313
53320241211220141213
645521004344512035
72650323066533405
oct314421670614267
954680701772655
1014055530240183
114529a0a436a73
1216b008077b61b
137ac57a664a33
14368411448475
1519593b0379a8
hexcc88ee318b7

14055530240183 has 2 divisors, whose sum is σ = 14055530240184. Its totient is φ = 14055530240182.

The previous prime is 14055530240119. The next prime is 14055530240237. The reversal of 14055530240183 is 38104203555041.

14055530240183 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 14055530240183 - 26 = 14055530240119 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 14055530240183.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (14055530246183) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7027765120091 + 7027765120092.

It is an arithmetic number, because the mean of its divisors is an integer number (7027765120092).

Almost surely, 214055530240183 is an apocalyptic number.

14055530240183 is a deficient number, since it is larger than the sum of its proper divisors (1).

14055530240183 is an equidigital number, since it uses as much as digits as its factorization.

14055530240183 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 288000, while the sum is 41.

The spelling of 14055530240183 in words is "fourteen trillion, fifty-five billion, five hundred thirty million, two hundred forty thousand, one hundred eighty-three".