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14055543401455 = 529347279350957
BaseRepresentation
bin1100110010001000111110…
…1010111110101111101111
31211202200210222122002121101
43030202033222332233233
53320241223102321310
645521005534543531
72650323316440433
oct314421752765757
954680728562541
1014055543401455
114529a16906256
1216b0085067ba7
137ac5802c247a
143684130b29c3
1519593c28743a
hexcc88fabebef

14055543401455 has 16 divisors (see below), whose sum is σ = 17498544009120. Its totient is φ = 10825408246912.

The previous prime is 14055543401429. The next prime is 14055543401527. The reversal of 14055543401455 is 55410434555041.

It is a cyclic number.

It is not a de Polignac number, because 14055543401455 - 27 = 14055543401327 is a prime.

It is a super-2 number, since 2×140555434014552 (a number of 27 digits) contains 22 as substring.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 139625164 + ... + 139725793.

It is an arithmetic number, because the mean of its divisors is an integer number (1093659000570).

Almost surely, 214055543401455 is an apocalyptic number.

14055543401455 is a deficient number, since it is larger than the sum of its proper divisors (3443000607665).

14055543401455 is a wasteful number, since it uses less digits than its factorization.

14055543401455 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 279351338.

The product of its (nonzero) digits is 2400000, while the sum is 46.

Adding to 14055543401455 its reverse (55410434555041), we get a palindrome (69465977956496).

The spelling of 14055543401455 in words is "fourteen trillion, fifty-five billion, five hundred forty-three million, four hundred one thousand, four hundred fifty-five".

Divisors: 1 5 29 145 347 1735 10063 50315 279350957 1396754785 8101177753 40505888765 96934782079 484673910395 2811108680291 14055543401455