Base | Representation |
---|---|
bin | 1100110010001000111110… |
… | …1010111110101111101111 |
3 | 1211202200210222122002121101 |
4 | 3030202033222332233233 |
5 | 3320241223102321310 |
6 | 45521005534543531 |
7 | 2650323316440433 |
oct | 314421752765757 |
9 | 54680728562541 |
10 | 14055543401455 |
11 | 4529a16906256 |
12 | 16b0085067ba7 |
13 | 7ac5802c247a |
14 | 3684130b29c3 |
15 | 19593c28743a |
hex | cc88fabebef |
14055543401455 has 16 divisors (see below), whose sum is σ = 17498544009120. Its totient is φ = 10825408246912.
The previous prime is 14055543401429. The next prime is 14055543401527. The reversal of 14055543401455 is 55410434555041.
It is a cyclic number.
It is not a de Polignac number, because 14055543401455 - 27 = 14055543401327 is a prime.
It is a super-2 number, since 2×140555434014552 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 139625164 + ... + 139725793.
It is an arithmetic number, because the mean of its divisors is an integer number (1093659000570).
Almost surely, 214055543401455 is an apocalyptic number.
14055543401455 is a deficient number, since it is larger than the sum of its proper divisors (3443000607665).
14055543401455 is a wasteful number, since it uses less digits than its factorization.
14055543401455 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 279351338.
The product of its (nonzero) digits is 2400000, while the sum is 46.
Adding to 14055543401455 its reverse (55410434555041), we get a palindrome (69465977956496).
The spelling of 14055543401455 in words is "fourteen trillion, fifty-five billion, five hundred forty-three million, four hundred one thousand, four hundred fifty-five".
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