Base | Representation |
---|---|
bin | 10100011101111001110… |
… | …010101011010000101001 |
3 | 11222110102020102202201211 |
4 | 110131321302223100221 |
5 | 141021001343231241 |
6 | 2554045221313121 |
7 | 203421215424304 |
oct | 24357162532051 |
9 | 4873366382654 |
10 | 1406497633321 |
11 | 4a2546279390 |
12 | 1a87092657a1 |
13 | a282ab09711 |
14 | 4c109555b3b |
15 | 268bd7e4781 |
hex | 14779cab429 |
1406497633321 has 4 divisors (see below), whose sum is σ = 1534361054544. Its totient is φ = 1278634212100.
The previous prime is 1406497633301. The next prime is 1406497633337. The reversal of 1406497633321 is 1233367946041.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 1406497633321 - 27 = 1406497633193 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (1406497633301) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 63931710595 + ... + 63931710616.
It is an arithmetic number, because the mean of its divisors is an integer number (383590263636).
Almost surely, 21406497633321 is an apocalyptic number.
1406497633321 is a gapful number since it is divisible by the number (11) formed by its first and last digit.
It is an amenable number.
1406497633321 is a deficient number, since it is larger than the sum of its proper divisors (127863421223).
1406497633321 is a wasteful number, since it uses less digits than its factorization.
1406497633321 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 127863421222.
The product of its (nonzero) digits is 1959552, while the sum is 49.
The spelling of 1406497633321 in words is "one trillion, four hundred six billion, four hundred ninety-seven million, six hundred thirty-three thousand, three hundred twenty-one".
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