Base | Representation |
---|---|
bin | 11010001100101101… |
… | …01000100111101011 |
3 | 1100022020020020210101 |
4 | 31012112220213223 |
5 | 212301200144210 |
6 | 10243402530231 |
7 | 1005356400142 |
oct | 150626504753 |
9 | 40266206711 |
10 | 14065240555 |
11 | 5a68509453 |
12 | 2886506977 |
13 | 1431ca2262 |
14 | 97601a759 |
15 | 574c1da3a |
hex | 3465a89eb |
14065240555 has 8 divisors (see below), whose sum is σ = 17460298800. Its totient is φ = 10864185696.
The previous prime is 14065240517. The next prime is 14065240571. The reversal of 14065240555 is 55504256041.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 14065240555 - 29 = 14065240043 is a prime.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 48500685 + ... + 48500974.
It is an arithmetic number, because the mean of its divisors is an integer number (2182537350).
Almost surely, 214065240555 is an apocalyptic number.
14065240555 is a deficient number, since it is larger than the sum of its proper divisors (3395058245).
14065240555 is an equidigital number, since it uses as much as digits as its factorization.
14065240555 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 97001693.
The product of its (nonzero) digits is 120000, while the sum is 37.
Adding to 14065240555 its reverse (55504256041), we get a palindrome (69569496596).
The spelling of 14065240555 in words is "fourteen billion, sixty-five million, two hundred forty thousand, five hundred fifty-five".
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