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14065771121 is a prime number
BaseRepresentation
bin11010001100110001…
…01010001001110001
31100022021020012120222
431012120222021301
5212301314133441
610243422142425
71005364040033
oct150630521161
940267205528
1014065771121
115a68841036
122886721a15
1314321298bc
14976117c53
15574cc5d4b
hex34662a271

14065771121 has 2 divisors, whose sum is σ = 14065771122. Its totient is φ = 14065771120.

The previous prime is 14065771103. The next prime is 14065771123. The reversal of 14065771121 is 12117756041.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 13633131121 + 432640000 = 116761^2 + 20800^2 .

It is an emirp because it is prime and its reverse (12117756041) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-14065771121 is a prime.

Together with 14065771123, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (14065771123) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7032885560 + 7032885561.

It is an arithmetic number, because the mean of its divisors is an integer number (7032885561).

Almost surely, 214065771121 is an apocalyptic number.

It is an amenable number.

14065771121 is a deficient number, since it is larger than the sum of its proper divisors (1).

14065771121 is an equidigital number, since it uses as much as digits as its factorization.

14065771121 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 11760, while the sum is 35.

The spelling of 14065771121 in words is "fourteen billion, sixty-five million, seven hundred seventy-one thousand, one hundred twenty-one".