14080433 has 2 divisors, whose sum is σ = 14080434. Its totient is φ = 14080432.

The previous prime is 14080427. The next prime is 14080477. The reversal of 14080433 is 33408041.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 8567329 + 5513104 = 2927^2 + 2348^2 .

It is an emirp because it is prime and its reverse (33408041) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 14080433 - 2¹⁰ = 14079409 is a prime.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 14080399 and 14080408.

It is not a weakly prime, because it can be changed into another prime (14080133) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7040216 + 7040217.

It is an arithmetic number, because the mean of its divisors is an integer number (7040217).

Almost surely, 2^14080433 is an apocalyptic number.

It is an amenable number.

14080433 is a deficient number, since it is larger than the sum of its proper divisors (1).

14080433 is an equidigital number, since it uses as much as digits as its factorization.

14080433 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1152, while the sum is 23.

The square root of 14080433 is about 3752.3903048590. The cubic root of 14080433 is about 241.4749047676.

Adding to 14080433 its reverse (33408041), we get a palindrome (47488474).

The spelling of 14080433 in words is "fourteen million, eighty thousand, four hundred thirty-three".