Base | Representation |
---|---|
bin | 11010001111100001… |
… | …00110101011000011 |
3 | 1100100212121111022022 |
4 | 31013300212223003 |
5 | 212323214404124 |
6 | 10250004232055 |
7 | 1006064020055 |
oct | 150760465303 |
9 | 40325544268 |
10 | 14088825539 |
11 | 5a7a858178 |
12 | 289239b62b |
13 | 1436b3c379 |
14 | 9791d98d5 |
15 | 576d2bc5e |
hex | 347c26ac3 |
14088825539 has 2 divisors, whose sum is σ = 14088825540. Its totient is φ = 14088825538.
The previous prime is 14088825521. The next prime is 14088825547. The reversal of 14088825539 is 93552888041.
14088825539 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is an emirp because it is prime and its reverse (93552888041) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 14088825539 - 216 = 14088760003 is a prime.
It is not a weakly prime, because it can be changed into another prime (14088825239) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7044412769 + 7044412770.
It is an arithmetic number, because the mean of its divisors is an integer number (7044412770).
Almost surely, 214088825539 is an apocalyptic number.
14088825539 is a deficient number, since it is larger than the sum of its proper divisors (1).
14088825539 is an equidigital number, since it uses as much as digits as its factorization.
14088825539 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2764800, while the sum is 53.
The spelling of 14088825539 in words is "fourteen billion, eighty-eight million, eight hundred twenty-five thousand, five hundred thirty-nine".
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