1409692540343 has 4 divisors (see below), whose sum is σ = 1409985194640. Its totient is φ = 1409399886048.

The previous prime is 1409692540337. The next prime is 1409692540357. The reversal of 1409692540343 is 3430452969041.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1409692540343 - 2⁶ = 1409692540279 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1409692540291 and 1409692540300.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1409692540363) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 146319923 + ... + 146329556.

It is an arithmetic number, because the mean of its divisors is an integer number (352496298660).

Almost surely, 2^{1409692540343} is an apocalyptic number.

1409692540343 is a deficient number, since it is larger than the sum of its proper divisors (292654297).

1409692540343 is an equidigital number, since it uses as much as digits as its factorization.

1409692540343 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 292654296.

The product of its (nonzero) digits is 2799360, while the sum is 50.

The spelling of 1409692540343 in words is "one trillion, four hundred nine billion, six hundred ninety-two million, five hundred forty thousand, three hundred forty-three".