14100224113 has 2 divisors, whose sum is σ = 14100224114. Its totient is φ = 14100224112.

The previous prime is 14100224111. The next prime is 14100224119. The reversal of 14100224113 is 31142200141.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 13991814369 + 108409744 = 118287^2 + 10412^2 .

It is a cyclic number.

It is not a de Polignac number, because 14100224113 - 2¹ = 14100224111 is a prime.

Together with 14100224111, it forms a pair of twin primes.

It is not a weakly prime, because it can be changed into another prime (14100224111) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7050112056 + 7050112057.

It is an arithmetic number, because the mean of its divisors is an integer number (7050112057).

Almost surely, 2^14100224113 is an apocalyptic number.

It is an amenable number.

14100224113 is a deficient number, since it is larger than the sum of its proper divisors (1).

14100224113 is an equidigital number, since it uses as much as digits as its factorization.

14100224113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 192, while the sum is 19.

Adding to 14100224113 its reverse (31142200141), we get a palindrome (45242424254).

The spelling of 14100224113 in words is "fourteen billion, one hundred million, two hundred twenty-four thousand, one hundred thirteen".