141002341242341 has 2 divisors, whose sum is σ = 141002341242342. Its totient is φ = 141002341242340.

The previous prime is 141002341242317. The next prime is 141002341242379. The reversal of 141002341242341 is 143242143200141.

141002341242341 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 93858874710241 + 47143466532100 = 9688079^2 + 6866110^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-141002341242341 is a prime.

It is a Sophie Germain prime.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 141002341242298 and 141002341242307.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (141002341242311) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70501170621170 + 70501170621171.

It is an arithmetic number, because the mean of its divisors is an integer number (70501170621171).

Almost surely, 2^{141002341242341} is an apocalyptic number.

It is an amenable number.

141002341242341 is a deficient number, since it is larger than the sum of its proper divisors (1).

141002341242341 is an equidigital number, since it uses as much as digits as its factorization.

141002341242341 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 18432, while the sum is 32.

Adding to 141002341242341 its reverse (143242143200141), we get a palindrome (284244484442482).

The spelling of 141002341242341 in words is "one hundred forty-one trillion, two billion, three hundred forty-one million, two hundred forty-two thousand, three hundred forty-one".