14100244422241 has 4 divisors (see below), whose sum is σ = 14100253143984. Its totient is φ = 14100235700500.

The previous prime is 14100244422227. The next prime is 14100244422247. The reversal of 14100244422241 is 14222444200141.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also a brilliant number, because the two primes have the same length.

It is a cyclic number.

It is not a de Polignac number, because 14100244422241 - 2¹¹ = 14100244420193 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (14100244422247) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1145695 + ... + 5432596.

It is an arithmetic number, because the mean of its divisors is an integer number (3525063285996).

Almost surely, 2^{14100244422241} is an apocalyptic number.

It is an amenable number.

14100244422241 is a deficient number, since it is larger than the sum of its proper divisors (8721743).

14100244422241 is an equidigital number, since it uses as much as digits as its factorization.

14100244422241 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 8721742.

The product of its (nonzero) digits is 16384, while the sum is 31.

Adding to 14100244422241 its reverse (14222444200141), we get a palindrome (28322688622382).

The spelling of 14100244422241 in words is "fourteen trillion, one hundred billion, two hundred forty-four million, four hundred twenty-two thousand, two hundred forty-one".