Base | Representation |
---|---|
bin | 1100110100101111100000… |
… | …0110100010110001000111 |
3 | 1211220222012022211012120122 |
4 | 3031023320012202301013 |
5 | 3322004300223132221 |
6 | 45553321352052155 |
7 | 2653465135036514 |
oct | 315137006426107 |
9 | 54828168735518 |
10 | 14100245130311 |
11 | 454697586881a |
12 | 16b887b69405b |
13 | 7b385548c6c2 |
14 | 36a653c9c30b |
15 | 196ba6908eab |
hex | cd2f81a2c47 |
14100245130311 has 8 divisors (see below), whose sum is σ = 14116931255904. Its totient is φ = 14083560784800.
The previous prime is 14100245130299. The next prime is 14100245130359. The reversal of 14100245130311 is 11303154200141.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 14100245130311 - 26 = 14100245130247 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (14100245138311) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 15754961 + ... + 16625861.
It is an arithmetic number, because the mean of its divisors is an integer number (1764616406988).
Almost surely, 214100245130311 is an apocalyptic number.
14100245130311 is a deficient number, since it is larger than the sum of its proper divisors (16686125593).
14100245130311 is an equidigital number, since it uses as much as digits as its factorization.
14100245130311 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 890041.
The product of its (nonzero) digits is 1440, while the sum is 26.
Adding to 14100245130311 its reverse (11303154200141), we get a palindrome (25403399330452).
The spelling of 14100245130311 in words is "fourteen trillion, one hundred billion, two hundred forty-five million, one hundred thirty thousand, three hundred eleven".
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