Search a number
-
+
1410040543151 = 4153339523367
BaseRepresentation
bin10100100001001100111…
…101110011011110101111
311222210120011001020100102
4110201030331303132233
5141100230334340101
62555432542221315
7203605055601422
oct24411475633657
94883504036312
101410040543151
114a3aa4143a39
121a933788483b
13a2c73b1b176
144c363cc39b9
1526a2987a86b
hex1484cf737af

1410040543151 has 4 divisors (see below), whose sum is σ = 1410380070672. Its totient is φ = 1409701015632.

The previous prime is 1410040543129. The next prime is 1410040543193. The reversal of 1410040543151 is 1513450400141.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1410040543151 - 230 = 1408966801327 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1410040546151) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 169757531 + ... + 169765836.

It is an arithmetic number, because the mean of its divisors is an integer number (352595017668).

Almost surely, 21410040543151 is an apocalyptic number.

1410040543151 is a deficient number, since it is larger than the sum of its proper divisors (339527521).

1410040543151 is an equidigital number, since it uses as much as digits as its factorization.

1410040543151 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 339527520.

The product of its (nonzero) digits is 4800, while the sum is 29.

Adding to 1410040543151 its reverse (1513450400141), we get a palindrome (2923490943292).

The spelling of 1410040543151 in words is "one trillion, four hundred ten billion, forty million, five hundred forty-three thousand, one hundred fifty-one".

Divisors: 1 4153 339523367 1410040543151