Base | Representation |
---|---|
bin | 1100110100110000100001… |
… | …0111111001000110000111 |
3 | 1211220222220100111012100110 |
4 | 3031030020113321012013 |
5 | 3322010330114114141 |
6 | 45553404423044103 |
7 | 2653504661254413 |
oct | 315141027710607 |
9 | 54828810435313 |
10 | 14100518113671 |
11 | 4546aa596a200 |
12 | 16b8936ba0633 |
13 | 7b3899bbb412 |
14 | 36a67c23bd43 |
15 | 196bc087ce16 |
hex | cd3085f9187 |
14100518113671 has 12 divisors (see below), whose sum is σ = 20665222139576. Its totient is φ = 8545768553520.
The previous prime is 14100518113637. The next prime is 14100518113673. The reversal of 14100518113671 is 17631181500141.
It is not a de Polignac number, because 14100518113671 - 26 = 14100518113607 is a prime.
It is a super-2 number, since 2×141005181136712 (a number of 27 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (14100518113673) by changing a digit.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 19422200896 + ... + 19422201621.
Almost surely, 214100518113671 is an apocalyptic number.
14100518113671 is a gapful number since it is divisible by the number (11) formed by its first and last digit.
14100518113671 is a deficient number, since it is larger than the sum of its proper divisors (6564704025905).
14100518113671 is a wasteful number, since it uses less digits than its factorization.
14100518113671 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 38844402542 (or 38844402531 counting only the distinct ones).
The product of its (nonzero) digits is 20160, while the sum is 39.
The spelling of 14100518113671 in words is "fourteen trillion, one hundred billion, five hundred eighteen million, one hundred thirteen thousand, six hundred seventy-one".
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