141010642711 has 2 divisors, whose sum is σ = 141010642712. Its totient is φ = 141010642710.

The previous prime is 141010642697. The next prime is 141010642733. The reversal of 141010642711 is 117246010141.

141010642711 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 141010642711 - 2⁷ = 141010642583 is a prime.

It is a super-3 number, since 3×141010642711³ (a number of 34 digits) contains 333 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 141010642711.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (141010642211) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70505321355 + 70505321356.

It is an arithmetic number, because the mean of its divisors is an integer number (70505321356).

Almost surely, 2^141010642711 is an apocalyptic number.

141010642711 is a deficient number, since it is larger than the sum of its proper divisors (1).

141010642711 is an equidigital number, since it uses as much as digits as its factorization.

141010642711 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1344, while the sum is 28.

Adding to 141010642711 its reverse (117246010141), we get a palindrome (258256652852).

The spelling of 141010642711 in words is "one hundred forty-one billion, ten million, six hundred forty-two thousand, seven hundred eleven".