Base | Representation |
---|---|
bin | 100000000011111111111110… |
… | …011011110111100010010011 |
3 | 200111021122111102120120212021 |
4 | 200003333332123313202103 |
5 | 121440321233020410303 |
6 | 1215524101422512311 |
7 | 41462543145313021 |
oct | 4003777633674223 |
9 | 614248442516767 |
10 | 141012340013203 |
11 | 40a26aa783175a |
12 | 13995177435697 |
13 | 608b53940b3a9 |
14 | 26b706857d711 |
15 | 11480c4287ebd |
hex | 803ffe6f7893 |
141012340013203 has 2 divisors, whose sum is σ = 141012340013204. Its totient is φ = 141012340013202.
The previous prime is 141012340013201. The next prime is 141012340013243. The reversal of 141012340013203 is 302310043210141.
It is a weak prime.
It is an emirp because it is prime and its reverse (302310043210141) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 141012340013203 - 21 = 141012340013201 is a prime.
Together with 141012340013201, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (141012340013201) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70506170006601 + 70506170006602.
It is an arithmetic number, because the mean of its divisors is an integer number (70506170006602).
Almost surely, 2141012340013203 is an apocalyptic number.
141012340013203 is a deficient number, since it is larger than the sum of its proper divisors (1).
141012340013203 is an equidigital number, since it uses as much as digits as its factorization.
141012340013203 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1728, while the sum is 25.
Adding to 141012340013203 its reverse (302310043210141), we get a palindrome (443322383223344).
The spelling of 141012340013203 in words is "one hundred forty-one trillion, twelve billion, three hundred forty million, thirteen thousand, two hundred three".
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