Base | Representation |
---|---|
bin | 11010010001000101… |
… | …11001100010110001 |
3 | 1100101210102100000220 |
4 | 31020202321202301 |
5 | 212340103310113 |
6 | 10251155003253 |
7 | 1006314051606 |
oct | 151042714261 |
9 | 40353370026 |
10 | 14102010033 |
11 | 5a87242951 |
12 | 2896899529 |
13 | 14397a7547 |
14 | 97ac6c6ad |
15 | 578083523 |
hex | 3488b98b1 |
14102010033 has 32 divisors (see below), whose sum is σ = 20017725696. Its totient is φ = 8810850048.
The previous prime is 14102010031. The next prime is 14102010047. The reversal of 14102010033 is 33001020141.
It is not a de Polignac number, because 14102010033 - 21 = 14102010031 is a prime.
It is a super-2 number, since 2×141020100332 (a number of 21 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 14102009994 and 14102010021.
It is not an unprimeable number, because it can be changed into a prime (14102010031) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 3204991 + ... + 3209387.
It is an arithmetic number, because the mean of its divisors is an integer number (625553928).
Almost surely, 214102010033 is an apocalyptic number.
It is an amenable number.
14102010033 is a deficient number, since it is larger than the sum of its proper divisors (5915715663).
14102010033 is a wasteful number, since it uses less digits than its factorization.
14102010033 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 5353.
The product of its (nonzero) digits is 72, while the sum is 15.
Adding to 14102010033 its reverse (33001020141), we get a palindrome (47103030174).
The spelling of 14102010033 in words is "fourteen billion, one hundred two million, ten thousand, thirty-three".
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