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1410201304021 is a prime number
BaseRepresentation
bin10100100001010110100…
…011000011101111010101
311222210222100112201210201
4110201112203003233111
5141101043013212041
62555500524020501
7203612050210126
oct24412643035725
94883870481721
101410201304021
114a4076965a64
121a9381691731
13a2c9b217043
144c37b3b004d
1526a38a33631
hex148568c3bd5

1410201304021 has 2 divisors, whose sum is σ = 1410201304022. Its totient is φ = 1410201304020.

The previous prime is 1410201303971. The next prime is 1410201304051. The reversal of 1410201304021 is 1204031020141.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1114576390225 + 295624913796 = 1055735^2 + 543714^2 .

It is a cyclic number.

It is not a de Polignac number, because 1410201304021 - 27 = 1410201303893 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 1410201304021.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1410201304051) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 705100652010 + 705100652011.

It is an arithmetic number, because the mean of its divisors is an integer number (705100652011).

Almost surely, 21410201304021 is an apocalyptic number.

It is an amenable number.

1410201304021 is a deficient number, since it is larger than the sum of its proper divisors (1).

1410201304021 is an equidigital number, since it uses as much as digits as its factorization.

1410201304021 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 192, while the sum is 19.

Adding to 1410201304021 its reverse (1204031020141), we get a palindrome (2614232324162).

The spelling of 1410201304021 in words is "one trillion, four hundred ten billion, two hundred one million, three hundred four thousand, twenty-one".