14102044031 has 2 divisors, whose sum is σ = 14102044032. Its totient is φ = 14102044030.

The previous prime is 14102044001. The next prime is 14102044039. The reversal of 14102044031 is 13044020141.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-14102044031 is a prime.

It is a super-2 number, since 2×14102044031² (a number of 21 digits) contains 22 as substring.

It is a Sophie Germain prime.

It is a junction number, because it is equal to n+sod(n) for n = 14102043994 and 14102044012.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (14102044039) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7051022015 + 7051022016.

It is an arithmetic number, because the mean of its divisors is an integer number (7051022016).

Almost surely, 2^14102044031 is an apocalyptic number.

14102044031 is a deficient number, since it is larger than the sum of its proper divisors (1).

14102044031 is an equidigital number, since it uses as much as digits as its factorization.

14102044031 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 384, while the sum is 20.

Adding to 14102044031 its reverse (13044020141), we get a palindrome (27146064172).

The spelling of 14102044031 in words is "fourteen billion, one hundred two million, forty-four thousand, thirty-one".