Search a number
-
+
14102055541 = 72014579363
BaseRepresentation
bin11010010001000110…
…00100101001110101
31100101210111122110101
431020203010221311
5212340111234131
610251155554101
71006314331360
oct151043045165
940353448411
1014102055541
115a87274062
1228968bb931
1314397c2182
1497ac810d7
15578091c61
hex3488c4a75

14102055541 has 4 divisors (see below), whose sum is σ = 16116634912. Its totient is φ = 12087476172.

The previous prime is 14102055523. The next prime is 14102055551. The reversal of 14102055541 is 14555020141.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 14555020141 = 34741945303.

It is a cyclic number.

It is not a de Polignac number, because 14102055541 - 29 = 14102055029 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (14102055511) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1007289675 + ... + 1007289688.

It is an arithmetic number, because the mean of its divisors is an integer number (4029158728).

Almost surely, 214102055541 is an apocalyptic number.

It is an amenable number.

14102055541 is a deficient number, since it is larger than the sum of its proper divisors (2014579371).

14102055541 is an equidigital number, since it uses as much as digits as its factorization.

14102055541 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2014579370.

The product of its (nonzero) digits is 4000, while the sum is 28.

Adding to 14102055541 its reverse (14555020141), we get a palindrome (28657075682).

The spelling of 14102055541 in words is "fourteen billion, one hundred two million, fifty-five thousand, five hundred forty-one".

Divisors: 1 7 2014579363 14102055541