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141025105435 = 528205021087
BaseRepresentation
bin1000001101010111000…
…0000101011000011011
3111111000021121122001011
42003111300011120123
54302304411333220
6144441441234351
713121506421614
oct2032560053033
9444007548034
10141025105435
1154898aa5015
12233b90329b7
13103b607c366
146b7b832c0b
153a05c1165a
hex20d5c0561b

141025105435 has 4 divisors (see below), whose sum is σ = 169230126528. Its totient is φ = 112820084344.

The previous prime is 141025105433. The next prime is 141025105439. The reversal of 141025105435 is 534501520141.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 141025105435 - 21 = 141025105433 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 141025105397 and 141025105406.

It is not an unprimeable number, because it can be changed into a prime (141025105433) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 14102510539 + ... + 14102510548.

It is an arithmetic number, because the mean of its divisors is an integer number (42307531632).

Almost surely, 2141025105435 is an apocalyptic number.

141025105435 is a deficient number, since it is larger than the sum of its proper divisors (28205021093).

141025105435 is an equidigital number, since it uses as much as digits as its factorization.

141025105435 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 28205021092.

The product of its (nonzero) digits is 12000, while the sum is 31.

Adding to 141025105435 its reverse (534501520141), we get a palindrome (675526625576).

The spelling of 141025105435 in words is "one hundred forty-one billion, twenty-five million, one hundred five thousand, four hundred thirty-five".

Divisors: 1 5 28205021087 141025105435