14103000211 has 4 divisors (see below), whose sum is σ = 14845263400. Its totient is φ = 13360737024.

The previous prime is 14103000203. The next prime is 14103000311. The reversal of 14103000211 is 11200030141.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 14103000211 - 2³ = 14103000203 is a prime.

It is a super-2 number, since 2×14103000211² (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 14103000191 and 14103000200.

It is not an unprimeable number, because it can be changed into a prime (14103000011) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 371131566 + ... + 371131603.

It is an arithmetic number, because the mean of its divisors is an integer number (3711315850).

Almost surely, 2^14103000211 is an apocalyptic number.

14103000211 is a deficient number, since it is larger than the sum of its proper divisors (742263189).

14103000211 is an equidigital number, since it uses as much as digits as its factorization.

14103000211 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 742263188.

The product of its (nonzero) digits is 24, while the sum is 13.

Adding to 14103000211 its reverse (11200030141), we get a palindrome (25303030352).

The spelling of 14103000211 in words is "fourteen billion, one hundred three million, two hundred eleven", and thus it is an aban number.