14103021634543 has 4 divisors (see below), whose sum is σ = 14103031416448. Its totient is φ = 14103011852640.

The previous prime is 14103021634517. The next prime is 14103021634577. The reversal of 14103021634543 is 34543612030141.

It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-14103021634543 is a prime.

It is a super-2 number, since 2×14103021634543² (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (14103021632543) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2254671 + ... + 5769712.

It is an arithmetic number, because the mean of its divisors is an integer number (3525757854112).

Almost surely, 2^{14103021634543} is an apocalyptic number.

14103021634543 is a deficient number, since it is larger than the sum of its proper divisors (9781905).

14103021634543 is an equidigital number, since it uses as much as digits as its factorization.

14103021634543 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 9781904.

The product of its (nonzero) digits is 103680, while the sum is 37.

Adding to 14103021634543 its reverse (34543612030141), we get a palindrome (48646633664684).

The spelling of 14103021634543 in words is "fourteen trillion, one hundred three billion, twenty-one million, six hundred thirty-four thousand, five hundred forty-three".