Base | Representation |
---|---|
bin | 1100110100111010001101… |
… | …1110011111101110100101 |
3 | 1211221020121200222122002202 |
4 | 3031032203132133232211 |
5 | 3322031142300011003 |
6 | 45554514541144245 |
7 | 2653626316506206 |
oct | 315164336375645 |
9 | 54836550878082 |
10 | 14103120313253 |
11 | 4548110827274 |
12 | 16b934255b085 |
13 | 7b3bc305159a |
14 | 36a847a935ad |
15 | 196cc4045088 |
hex | cd3a379fba5 |
14103120313253 has 2 divisors, whose sum is σ = 14103120313254. Its totient is φ = 14103120313252.
The previous prime is 14103120313159. The next prime is 14103120313283. The reversal of 14103120313253 is 35231302130141.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 13736348362564 + 366771950689 = 3706258^2 + 605617^2 .
It is a cyclic number.
It is not a de Polignac number, because 14103120313253 - 216 = 14103120247717 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (14103120313283) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7051560156626 + 7051560156627.
It is an arithmetic number, because the mean of its divisors is an integer number (7051560156627).
Almost surely, 214103120313253 is an apocalyptic number.
It is an amenable number.
14103120313253 is a deficient number, since it is larger than the sum of its proper divisors (1).
14103120313253 is an equidigital number, since it uses as much as digits as its factorization.
14103120313253 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 6480, while the sum is 29.
Adding to 14103120313253 its reverse (35231302130141), we get a palindrome (49334422443394).
The spelling of 14103120313253 in words is "fourteen trillion, one hundred three billion, one hundred twenty million, three hundred thirteen thousand, two hundred fifty-three".
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