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14103334110011 = 37808337302217
BaseRepresentation
bin1100110100111011000000…
…1110000100001100111011
31211221021011121021122010012
43031032300032010030323
53322032112013010021
645554552055412135
72653634523655316
oct315166016041473
954837147248105
1014103334110011
114548210482a03
1216b93a208404b
137b3c28429643
1436a86822797d
15196cd7bc735b
hexcd3b038433b

14103334110011 has 4 divisors (see below), whose sum is σ = 14103371790312. Its totient is φ = 14103296429712.

The previous prime is 14103334109993. The next prime is 14103334110023. The reversal of 14103334110011 is 11001143330141.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 14103334110011 - 210 = 14103334108987 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (14103334118011) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 18273026 + ... + 19029191.

It is an arithmetic number, because the mean of its divisors is an integer number (3525842947578).

Almost surely, 214103334110011 is an apocalyptic number.

14103334110011 is a deficient number, since it is larger than the sum of its proper divisors (37680301).

14103334110011 is an equidigital number, since it uses as much as digits as its factorization.

14103334110011 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 37680300.

The product of its (nonzero) digits is 432, while the sum is 23.

Adding to 14103334110011 its reverse (11001143330141), we get a palindrome (25104477440152).

The spelling of 14103334110011 in words is "fourteen trillion, one hundred three billion, three hundred thirty-four million, one hundred ten thousand, eleven".

Divisors: 1 378083 37302217 14103334110011