Base | Representation |
---|---|
bin | 11010010001010101… |
… | …11001010101010011 |
3 | 1100101221100211121021 |
4 | 31020222321111103 |
5 | 212341122400243 |
6 | 10251311540311 |
7 | 1006340632336 |
oct | 151052712523 |
9 | 40357324537 |
10 | 14104106323 |
11 | 5a8844491a |
12 | 289752a697 |
13 | 143a05c758 |
14 | 97b25661d |
15 | 5783496ed |
hex | 348ab9553 |
14104106323 has 4 divisors (see below), whose sum is σ = 14104798360. Its totient is φ = 14103414288.
The previous prime is 14104106279. The next prime is 14104106327. The reversal of 14104106323 is 32360140141.
14104106323 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 14104106323 - 213 = 14104098131 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (14104106327) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 314490 + ... + 356527.
It is an arithmetic number, because the mean of its divisors is an integer number (3526199590).
Almost surely, 214104106323 is an apocalyptic number.
14104106323 is a deficient number, since it is larger than the sum of its proper divisors (692037).
14104106323 is an equidigital number, since it uses as much as digits as its factorization.
14104106323 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 692036.
The product of its (nonzero) digits is 1728, while the sum is 25.
Adding to 14104106323 its reverse (32360140141), we get a palindrome (46464246464).
The spelling of 14104106323 in words is "fourteen billion, one hundred four million, one hundred six thousand, three hundred twenty-three".
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