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14104131 = 34701377
BaseRepresentation
bin110101110011…
…011001000011
3222112120020020
4311303121003
512102313011
61222144523
7230611626
oct65633103
928476206
1014104131
117a63708
124882143
132bca952
141c31dbd
151389006
hexd73643

14104131 has 4 divisors (see below), whose sum is σ = 18805512. Its totient is φ = 9402752.

The previous prime is 14104087. The next prime is 14104133. The reversal of 14104131 is 13140141.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 14104131 - 217 = 13973059 is a prime.

It is a super-2 number, since 2×141041312 = 397853022530322, which contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 14104131.

It is not an unprimeable number, because it can be changed into a prime (14104133) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2350686 + ... + 2350691.

It is an arithmetic number, because the mean of its divisors is an integer number (4701378).

Almost surely, 214104131 is an apocalyptic number.

14104131 is a deficient number, since it is larger than the sum of its proper divisors (4701381).

14104131 is an equidigital number, since it uses as much as digits as its factorization.

14104131 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4701380.

The product of its (nonzero) digits is 48, while the sum is 15.

The square root of 14104131 is about 3755.5466978857. The cubic root of 14104131 is about 241.6102998675.

Adding to 14104131 its reverse (13140141), we get a palindrome (27244272).

The spelling of 14104131 in words is "fourteen million, one hundred four thousand, one hundred thirty-one".

Divisors: 1 3 4701377 14104131