14104413421 has 4 divisors (see below), whose sum is σ = 16119329632. Its totient is φ = 12089497212.

The previous prime is 14104413419. The next prime is 14104413461. The reversal of 14104413421 is 12431440141.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 14104413421 - 2¹ = 14104413419 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (14104413461) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1007458095 + ... + 1007458108.

It is an arithmetic number, because the mean of its divisors is an integer number (4029832408).

Almost surely, 2^14104413421 is an apocalyptic number.

It is an amenable number.

14104413421 is a deficient number, since it is larger than the sum of its proper divisors (2014916211).

14104413421 is an equidigital number, since it uses as much as digits as its factorization.

14104413421 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2014916210.

The product of its (nonzero) digits is 1536, while the sum is 25.

Adding to 14104413421 its reverse (12431440141), we get a palindrome (26535853562).

The spelling of 14104413421 in words is "fourteen billion, one hundred four million, four hundred thirteen thousand, four hundred twenty-one".