141044311113 has 4 divisors (see below), whose sum is σ = 188059081488. Its totient is φ = 94029540740.

The previous prime is 141044311099. The next prime is 141044311117. The reversal of 141044311113 is 311113440141.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 141044311113 - 2⁸ = 141044310857 is a prime.

It is a Curzon number.

It is not an unprimeable number, because it can be changed into a prime (141044311117) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 23507385183 + ... + 23507385188.

It is an arithmetic number, because the mean of its divisors is an integer number (47014770372).

Almost surely, 2^141044311113 is an apocalyptic number.

It is an amenable number.

141044311113 is a deficient number, since it is larger than the sum of its proper divisors (47014770375).

141044311113 is an equidigital number, since it uses as much as digits as its factorization.

141044311113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 47014770374.

The product of its (nonzero) digits is 576, while the sum is 24.

Adding to 141044311113 its reverse (311113440141), we get a palindrome (452157751254).

The spelling of 141044311113 in words is "one hundred forty-one billion, forty-four million, three hundred eleven thousand, one hundred thirteen".