Search a number
-
+
141050543551 = 181779284771
BaseRepresentation
bin1000001101011101000…
…1000111110110111111
3111111002001111000120121
42003113101013312333
54302332414343201
6144444150355411
713122235560331
oct2032721076677
9444061430517
10141050543551
115490139a055
122340565bb67
13103bb417ab8
146b80d75451
153a080889a1
hex20d7447dbf

141050543551 has 4 divisors (see below), whose sum is σ = 141829828504. Its totient is φ = 140271258600.

The previous prime is 141050543533. The next prime is 141050543581. The reversal of 141050543551 is 155345050141.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 155345050141 = 1131374734957.

It is a cyclic number.

It is not a de Polignac number, because 141050543551 - 27 = 141050543423 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (141050543581) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 389642205 + ... + 389642566.

It is an arithmetic number, because the mean of its divisors is an integer number (35457457126).

Almost surely, 2141050543551 is an apocalyptic number.

141050543551 is a deficient number, since it is larger than the sum of its proper divisors (779284953).

141050543551 is an equidigital number, since it uses as much as digits as its factorization.

141050543551 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 779284952.

The product of its (nonzero) digits is 30000, while the sum is 34.

Adding to 141050543551 its reverse (155345050141), we get a palindrome (296395593692).

The spelling of 141050543551 in words is "one hundred forty-one billion, fifty million, five hundred forty-three thousand, five hundred fifty-one".

Divisors: 1 181 779284771 141050543551