Base | Representation |
---|---|
bin | 1100110101010011111000… |
… | …1101101011010101101101 |
3 | 1211221220101221200001212211 |
4 | 3031110332031223111231 |
5 | 3322134300400341031 |
6 | 50002014423530421 |
7 | 2654262143331463 |
oct | 315247615532555 |
9 | 54856357601784 |
10 | 14110011340141 |
11 | 4550027610812 |
12 | 16ba7462b9a11 |
13 | 7b47508c16a2 |
14 | 36acdcd64833 |
15 | 197078ed5bb1 |
hex | cd53e36b56d |
14110011340141 has 2 divisors, whose sum is σ = 14110011340142. Its totient is φ = 14110011340140.
The previous prime is 14110011340097. The next prime is 14110011340147. The reversal of 14110011340141 is 14104311001141.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 13019179404100 + 1090831936041 = 3608210^2 + 1044429^2 .
It is a cyclic number.
It is not a de Polignac number, because 14110011340141 - 243 = 5313918317933 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (14110011340147) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7055005670070 + 7055005670071.
It is an arithmetic number, because the mean of its divisors is an integer number (7055005670071).
Almost surely, 214110011340141 is an apocalyptic number.
It is an amenable number.
14110011340141 is a deficient number, since it is larger than the sum of its proper divisors (1).
14110011340141 is an equidigital number, since it uses as much as digits as its factorization.
14110011340141 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 192, while the sum is 22.
Adding to 14110011340141 its reverse (14104311001141), we get a palindrome (28214322341282).
The spelling of 14110011340141 in words is "fourteen trillion, one hundred ten billion, eleven million, three hundred forty thousand, one hundred forty-one".
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