Base | Representation |
---|---|
bin | 10100100010000110011… |
… | …010010111000100000001 |
3 | 11222220001022120200200120 |
4 | 110202012122113010001 |
5 | 141104214102031431 |
6 | 3000112331410453 |
7 | 203641000626342 |
oct | 24420632270401 |
9 | 4886038520616 |
10 | 1411004330241 |
11 | 4a44491834a0 |
12 | 1a95665b3a29 |
13 | a30986b949c |
14 | 4c415cc60c9 |
15 | 26a842a7196 |
hex | 14886697101 |
1411004330241 has 16 divisors (see below), whose sum is σ = 2083002325248. Its totient is φ = 842390643600.
The previous prime is 1411004330209. The next prime is 1411004330251. The reversal of 1411004330241 is 1420334001141.
It is not a de Polignac number, because 1411004330241 - 25 = 1411004330209 is a prime.
It is not an unprimeable number, because it can be changed into a prime (1411004330251) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 319085155 + ... + 319089576.
It is an arithmetic number, because the mean of its divisors is an integer number (130187645328).
Almost surely, 21411004330241 is an apocalyptic number.
1411004330241 is a gapful number since it is divisible by the number (11) formed by its first and last digit.
It is an amenable number.
1411004330241 is a deficient number, since it is larger than the sum of its proper divisors (671997995007).
1411004330241 is a wasteful number, since it uses less digits than its factorization.
1411004330241 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 638174812.
The product of its (nonzero) digits is 1152, while the sum is 24.
Adding to 1411004330241 its reverse (1420334001141), we get a palindrome (2831338331382).
The spelling of 1411004330241 in words is "one trillion, four hundred eleven billion, four million, three hundred thirty thousand, two hundred forty-one".
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