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1411004330241 = 31167638174731
BaseRepresentation
bin10100100010000110011…
…010010111000100000001
311222220001022120200200120
4110202012122113010001
5141104214102031431
63000112331410453
7203641000626342
oct24420632270401
94886038520616
101411004330241
114a44491834a0
121a95665b3a29
13a30986b949c
144c415cc60c9
1526a842a7196
hex14886697101

1411004330241 has 16 divisors (see below), whose sum is σ = 2083002325248. Its totient is φ = 842390643600.

The previous prime is 1411004330209. The next prime is 1411004330251. The reversal of 1411004330241 is 1420334001141.

It is not a de Polignac number, because 1411004330241 - 25 = 1411004330209 is a prime.

It is not an unprimeable number, because it can be changed into a prime (1411004330251) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 319085155 + ... + 319089576.

It is an arithmetic number, because the mean of its divisors is an integer number (130187645328).

Almost surely, 21411004330241 is an apocalyptic number.

1411004330241 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

It is an amenable number.

1411004330241 is a deficient number, since it is larger than the sum of its proper divisors (671997995007).

1411004330241 is a wasteful number, since it uses less digits than its factorization.

1411004330241 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 638174812.

The product of its (nonzero) digits is 1152, while the sum is 24.

Adding to 1411004330241 its reverse (1420334001141), we get a palindrome (2831338331382).

The spelling of 1411004330241 in words is "one trillion, four hundred eleven billion, four million, three hundred thirty thousand, two hundred forty-one".

Divisors: 1 3 11 33 67 201 737 2211 638174731 1914524193 7019922041 21059766123 42757706977 128273120931 470334776747 1411004330241