Base | Representation |
---|---|
bin | 1000001101101000111… |
… | …1111011001100111011 |
3 | 111111012112121011220112 |
4 | 2003122033323030323 |
5 | 4302433220424321 |
6 | 144453134414535 |
7 | 13123413660401 |
oct | 2033217731473 |
9 | 444175534815 |
10 | 141100561211 |
11 | 54927652065 |
12 | 2341a36144b |
13 | 103c88ab24c |
14 | 6b87875471 |
15 | 3a0c668a5b |
hex | 20da3fb33b |
141100561211 has 2 divisors, whose sum is σ = 141100561212. Its totient is φ = 141100561210.
The previous prime is 141100561201. The next prime is 141100561219. The reversal of 141100561211 is 112165001141.
It is a strong prime.
It is an emirp because it is prime and its reverse (112165001141) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-141100561211 is a prime.
It is not a weakly prime, because it can be changed into another prime (141100561219) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70550280605 + 70550280606.
It is an arithmetic number, because the mean of its divisors is an integer number (70550280606).
Almost surely, 2141100561211 is an apocalyptic number.
141100561211 is a deficient number, since it is larger than the sum of its proper divisors (1).
141100561211 is an equidigital number, since it uses as much as digits as its factorization.
141100561211 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 240, while the sum is 23.
Adding to 141100561211 its reverse (112165001141), we get a palindrome (253265562352).
The spelling of 141100561211 in words is "one hundred forty-one billion, one hundred million, five hundred sixty-one thousand, two hundred eleven".
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