Base | Representation |
---|---|
bin | 11010010010000011… |
… | …01000001110001111 |
3 | 1100102100120121010102 |
4 | 31021001220032033 |
5 | 212344134044201 |
6 | 10252043401315 |
7 | 1006442402231 |
oct | 151101501617 |
9 | 40370517112 |
10 | 14110065551 |
11 | 5a908450aa |
12 | 289952323b |
13 | 143b36801a |
14 | 97bd68251 |
15 | 578b2526b |
hex | 34906838f |
14110065551 has 8 divisors (see below), whose sum is σ = 15254125680. Its totient is φ = 13006147968.
The previous prime is 14110065547. The next prime is 14110065601. The reversal of 14110065551 is 15556001141.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 14110065551 - 22 = 14110065547 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (14110067551) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 10034906 + ... + 10036311.
It is an arithmetic number, because the mean of its divisors is an integer number (1906765710).
Almost surely, 214110065551 is an apocalyptic number.
14110065551 is a deficient number, since it is larger than the sum of its proper divisors (1144060129).
14110065551 is a wasteful number, since it uses less digits than its factorization.
14110065551 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 20071273.
The product of its (nonzero) digits is 3000, while the sum is 29.
Adding to 14110065551 its reverse (15556001141), we get a palindrome (29666066692).
The spelling of 14110065551 in words is "fourteen billion, one hundred ten million, sixty-five thousand, five hundred fifty-one".
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