Base | Representation |
---|---|
bin | 10100100010000110110… |
… | …000011000001011110010 |
3 | 11222220001201102221001111 |
4 | 110202012300120023302 |
5 | 141104222041231002 |
6 | 3000113055223534 |
7 | 203641100655544 |
oct | 24420660301362 |
9 | 4886051387044 |
10 | 1411010102002 |
11 | 4a4451465946 |
12 | 1a9568517baa |
13 | a309995a627 |
14 | 4c416989694 |
15 | 26a84a473d7 |
hex | 14886c182f2 |
1411010102002 has 4 divisors (see below), whose sum is σ = 2116515153006. Its totient is φ = 705505051000.
The previous prime is 1411010101987. The next prime is 1411010102041. The reversal of 1411010102002 is 2002010101141.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 762741969201 + 648268132801 = 873351^2 + 805151^2 .
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 352752525499 + ... + 352752525502.
Almost surely, 21411010102002 is an apocalyptic number.
1411010102002 is a deficient number, since it is larger than the sum of its proper divisors (705505051004).
1411010102002 is an equidigital number, since it uses as much as digits as its factorization.
1411010102002 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 705505051003.
The product of its (nonzero) digits is 16, while the sum is 13.
Adding to 1411010102002 its reverse (2002010101141), we get a palindrome (3413020203143).
The spelling of 1411010102002 in words is "one trillion, four hundred eleven billion, ten million, one hundred two thousand, two".
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