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14110120344211 is a prime number
BaseRepresentation
bin1100110101010100010010…
…1101011111101010010011
31211221220200112210001100121
43031111010231133222103
53322140011302003321
650002033320131111
72654264636004553
oct315250455375223
954856615701317
1014110120344211
1145500830a2121
1216ba776906a97
137b476a368638
1436ad0d61b163
15197083868441
hexcd544b5fa93

14110120344211 has 2 divisors, whose sum is σ = 14110120344212. Its totient is φ = 14110120344210.

The previous prime is 14110120344209. The next prime is 14110120344217. The reversal of 14110120344211 is 11244302101141.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 14110120344211 - 21 = 14110120344209 is a prime.

It is a super-2 number, since 2×141101203442112 (a number of 27 digits) contains 22 as substring.

Together with 14110120344209, it forms a pair of twin primes.

It is not a weakly prime, because it can be changed into another prime (14110120344217) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7055060172105 + 7055060172106.

It is an arithmetic number, because the mean of its divisors is an integer number (7055060172106).

Almost surely, 214110120344211 is an apocalyptic number.

14110120344211 is a deficient number, since it is larger than the sum of its proper divisors (1).

14110120344211 is an equidigital number, since it uses as much as digits as its factorization.

14110120344211 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 768, while the sum is 25.

Adding to 14110120344211 its reverse (11244302101141), we get a palindrome (25354422445352).

The spelling of 14110120344211 in words is "fourteen trillion, one hundred ten billion, one hundred twenty million, three hundred forty-four thousand, two hundred eleven".