14110120344251 has 4 divisors (see below), whose sum is σ = 14111410482312. Its totient is φ = 14108830206192.

The previous prime is 14110120344233. The next prime is 14110120344361. The reversal of 14110120344251 is 15244302101141.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-14110120344251 is a prime.

It is a super-2 number, since 2×14110120344251² (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (14110120344211) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 645052625 + ... + 645074498.

It is an arithmetic number, because the mean of its divisors is an integer number (3527852620578).

Almost surely, 2^{14110120344251} is an apocalyptic number.

14110120344251 is a deficient number, since it is larger than the sum of its proper divisors (1290138061).

14110120344251 is a wasteful number, since it uses less digits than its factorization.

14110120344251 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1290138060.

The product of its (nonzero) digits is 3840, while the sum is 29.

Adding to 14110120344251 its reverse (15244302101141), we get a palindrome (29354422445392).

The spelling of 14110120344251 in words is "fourteen trillion, one hundred ten billion, one hundred twenty million, three hundred forty-four thousand, two hundred fifty-one".