Base | Representation |
---|---|
bin | 1100110101010100101011… |
… | …0101001001100011101011 |
3 | 1211221220221200222012222221 |
4 | 3031111022311021203223 |
5 | 3322140214042422443 |
6 | 50002051424454511 |
7 | 2654300323460005 |
oct | 315251265114353 |
9 | 54856850865887 |
10 | 14110223014123 |
11 | 4550126047595 |
12 | 16ba7a517a437 |
13 | 7b4785705472 |
14 | 36ad1d105375 |
15 | 19708c898eed |
hex | cd54ad498eb |
14110223014123 has 4 divisors (see below), whose sum is σ = 14110740449008. Its totient is φ = 14109705579240.
The previous prime is 14110223014099. The next prime is 14110223014163. The reversal of 14110223014123 is 32141032201141.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 14110223014123 - 29 = 14110223013611 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (14110223014163) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 258676536 + ... + 258731077.
It is an arithmetic number, because the mean of its divisors is an integer number (3527685112252).
Almost surely, 214110223014123 is an apocalyptic number.
14110223014123 is a deficient number, since it is larger than the sum of its proper divisors (517434885).
14110223014123 is an equidigital number, since it uses as much as digits as its factorization.
14110223014123 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 517434884.
The product of its (nonzero) digits is 1152, while the sum is 25.
Adding to 14110223014123 its reverse (32141032201141), we get a palindrome (46251255215264).
The spelling of 14110223014123 in words is "fourteen trillion, one hundred ten billion, two hundred twenty-three million, fourteen thousand, one hundred twenty-three".
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