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14110223014334 = 27055111507167
BaseRepresentation
bin1100110101010100101011…
…0101001001100110111110
31211221220221200222020021202
43031111022311021212332
53322140214042424314
650002051424455502
72654300323460426
oct315251265114676
954856850866252
1014110223014334
114550126047767
1216ba7a517a592
137b47857055a5
1436ad1d105486
1519708c8990de
hexcd54ad499be

14110223014334 has 4 divisors (see below), whose sum is σ = 21165334521504. Its totient is φ = 7055111507166.

The previous prime is 14110223014331. The next prime is 14110223014339. The reversal of 14110223014334 is 43341032201141.

It is a semiprime because it is the product of two primes.

It is a junction number, because it is equal to n+sod(n) for n = 14110223014297 and 14110223014306.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (14110223014331) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3527555753582 + ... + 3527555753585.

It is an arithmetic number, because the mean of its divisors is an integer number (5291333630376).

Almost surely, 214110223014334 is an apocalyptic number.

14110223014334 is a deficient number, since it is larger than the sum of its proper divisors (7055111507170).

14110223014334 is an equidigital number, since it uses as much as digits as its factorization.

14110223014334 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 7055111507169.

The product of its (nonzero) digits is 6912, while the sum is 29.

Adding to 14110223014334 its reverse (43341032201141), we get a palindrome (57451255215475).

The spelling of 14110223014334 in words is "fourteen trillion, one hundred ten billion, two hundred twenty-three million, fourteen thousand, three hundred thirty-four".

Divisors: 1 2 7055111507167 14110223014334