Base | Representation |
---|---|
bin | 10100100010000111101… |
… | …101010011110111111011 |
3 | 11222220002211111110001212 |
4 | 110202013231103313323 |
5 | 141104240133401011 |
6 | 3000114425433335 |
7 | 203641353513461 |
oct | 24420755236773 |
9 | 4886084443055 |
10 | 1411026075131 |
11 | 4a445a485782 |
12 | 1a957193b84b |
13 | a30a0060b9a |
14 | 4c418b46831 |
15 | 26a8615008b |
hex | 14887b53dfb |
1411026075131 has 2 divisors, whose sum is σ = 1411026075132. Its totient is φ = 1411026075130.
The previous prime is 1411026075089. The next prime is 1411026075133. The reversal of 1411026075131 is 1315706201141.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1411026075131 - 238 = 1136148168187 is a prime.
It is a super-2 number, since 2×14110260751312 (a number of 25 digits) contains 22 as substring.
It is a Sophie Germain prime.
Together with 1411026075133, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (1411026075133) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 705513037565 + 705513037566.
It is an arithmetic number, because the mean of its divisors is an integer number (705513037566).
Almost surely, 21411026075131 is an apocalyptic number.
1411026075131 is a deficient number, since it is larger than the sum of its proper divisors (1).
1411026075131 is an equidigital number, since it uses as much as digits as its factorization.
1411026075131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5040, while the sum is 32.
The spelling of 1411026075131 in words is "one trillion, four hundred eleven billion, twenty-six million, seventy-five thousand, one hundred thirty-one".
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