1411032001 has 2 divisors, whose sum is σ = 1411032002. Its totient is φ = 1411032000.

The previous prime is 1411031981. The next prime is 1411032013. The reversal of 1411032001 is 1002301141.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1098591025 + 312440976 = 33145^2 + 17676^2 .

It is an emirp because it is prime and its reverse (1002301141) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1411032001 - 2⁵ = 1411031969 is a prime.

It is a super-2 number, since 2×1411032001² = 3982022615692128002, which contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (1411032041) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 705516000 + 705516001.

It is an arithmetic number, because the mean of its divisors is an integer number (705516001).

Almost surely, 2^1411032001 is an apocalyptic number.

It is an amenable number.

1411032001 is a deficient number, since it is larger than the sum of its proper divisors (1).

1411032001 is an equidigital number, since it uses as much as digits as its factorization.

1411032001 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 24, while the sum is 13.

The square root of 1411032001 is about 37563.7059007761. The cubic root of 1411032001 is about 1121.6196806556.

Adding to 1411032001 its reverse (1002301141), we get a palindrome (2413333142).

The spelling of 1411032001 in words is "one billion, four hundred eleven million, thirty-two thousand, one".